From: Maringanti Krishna (maringanti9$##$yahoo.com)
Date: Wed Jan 14 2004 - 00:11:49 EST
Can any one or all of you suggest me, which of the following arguments is correct? If both are incorrect, how to explain the equivalent weight of chlorine in the disproportionation reaction with hot concentrated alkali, for example KOH.
Three moles of chlorine gas reacts with six moles of hot KOH. here One Chlorine atom apparently loses five electrons which is gained by 5 other Chlorine atoms. Net number of electron transfered per atom = 5/6. Since equivalent weight is atomic weight / net no. of electrons transferred, i.e atomic weight of chlorine*6/5. i.e. 1.2 times the atomic weight of chlorine.
Another possibility is, the equivalent weight can be Atomic Weight / 4. This is because, one chlorine atom becomes Cl(+5) and the other five chlorine atoms become Cl(-1). Net variation in charge is +5 + ( -1) = +4. Hence, the equivalent weight is Atomic Weight/ 4.
Any explaination is highly appreciated!
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